-8a^2=-8-2a

Solution for -8a^2=-8-2a equation:

-8a^2=-8-2a

We move all terms to the left:

-8a^2-(-8-2a)=0

We add all the numbers together, and all the variables

-8a^2-(-2a-8)=0

We get rid of parentheses

-8a^2+2a+8=0

a = -8; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-8)·8
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{65}}{2*-8}=\frac{-2-2\sqrt{65}}{-16}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{65}}{2*-8}=\frac{-2+2\sqrt{65}}{-16}
$